Find Remainder of x^3-4x^2-9x+7 by x+1 using Remainder Theorem
The Remainder Theorem is an approach to Euclidean polynomial division. According to this theorem, dividing a polynomial P(x) by a factor (x - a), which is not an element of the polynomial, yields a smaller polynomial and a remainder. Here you can check the answer for Find Remainder of x^3-4x^2-9x+7 by x+1 using Remainder Theorem.
Ex: x^2+2x+1,x+1 (or) x^2-1,x-1 (or) x^3-1,x+1
How to Find Remainder of x^3-4x^2-9x+7 by x+1 using Remainder Theorem?
Let p(x) = x^3-4x^2-9x+7
The zero of x+1 is = -1.
So after P(x) is divided by x+1 we get the remainder i.e. P(-1).
Now, p(-1) = x^3-4x^2-9x+7 .
= (7)+(x^3)+(-9.x)+(-4.x^2)
By putting x = (-1) we can rewrite it as
= (7)+((-1)^3)+(-9.(-1))+(-4.(-1)^2)
= (7)+(-1)+(9)+(-4)
= 11
∴The remainder of given polynomial is 11.
FAQs on Remainder Theorem of x^3-4x^2-9x+7 by x+1
1. What is the remainder of x^3-4x^2-9x+7 by x+1?
The Remainder of x^3-4x^2-9x+7 divided by x+1 is 11.
2. How to Find Remainder of x^3-4x^2-9x+7 by x+1 using Remainder Theorem?
Consider x+1 = 0 so that x = -1.
Substitute x = -1 in expression x^3-4x^2-9x+7 to get the remiander
Thus, x^3-4x^2-9x+7 divided by x+1 remainder is 11.
3. Where can I obtain detailed solution steps for Remainder Theorem of x^3-4x^2-9x+7?
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