Find Remainder of x^2+5x+6 by x-1 using Remainder Theorem
The Remainder Theorem is an approach to Euclidean polynomial division. According to this theorem, dividing a polynomial P(x) by a factor (x - a), which is not an element of the polynomial, yields a smaller polynomial and a remainder. Here you can check the answer for Find Remainder of x^2+5x+6 by x-1 using Remainder Theorem.
Ex: x^2+2x+1,x+1 (or) x^2-1,x-1 (or) x^3-1,x+1
How to Find Remainder of x^2+5x+6 by x-1 using Remainder Theorem?
Let p(x) = x^2+5x+6
The zero of x-1 is = 1.
So after P(x) is divided by x-1 we get the remainder i.e. P(1).
Now, p(1) = x^2+5x+6 .
= (6)+(x^2)+(5.x)
By putting x = (1) we can rewrite it as
= (6)+((1)^2)+(5.(1))
= (6)+(1)+(5)
= 12
∴The remainder of given polynomial is 12.
FAQs on Remainder Theorem of x^2+5x+6 by x-1
1. What is the remainder of x^2+5x+6 by x-1?
The Remainder of x^2+5x+6 divided by x-1 is 12.
2. How to Find Remainder of x^2+5x+6 by x-1 using Remainder Theorem?
Consider x-1 = 0 so that x = 1.
Substitute x = 1 in expression x^2+5x+6 to get the remiander
Thus, x^2+5x+6 divided by x-1 remainder is 12.
3. Where can I obtain detailed solution steps for Remainder Theorem of x^2+5x+6?
The detailed steps for the Remainder Theorem of x^2+5x+6 are compiled exclusively on our output page.