Find Remainder of x^2-4x+2 by x+6 using Remainder Theorem
The Remainder Theorem is an approach to Euclidean polynomial division. According to this theorem, dividing a polynomial P(x) by a factor (x - a), which is not an element of the polynomial, yields a smaller polynomial and a remainder. Here you can check the answer for Find Remainder of x^2-4x+2 by x+6 using Remainder Theorem.
Ex: x^2+2x+1,x+1 (or) x^2-1,x-1 (or) x^3-1,x+1
How to Find Remainder of x^2-4x+2 by x+6 using Remainder Theorem?
Let p(x) = x^2-4x+2
The zero of x+6 is = -6.
So after P(x) is divided by x+6 we get the remainder i.e. P(-6).
Now, p(-6) = x^2-4x+2 .
= (2)+(x^2)+(-4.x)
By putting x = (-6) we can rewrite it as
= (2)+((-6)^2)+(-4.(-6))
= (2)+(36)+(24)
= 62
∴The remainder of given polynomial is 62.
FAQs on Remainder Theorem of x^2-4x+2 by x+6
1. What is the remainder of x^2-4x+2 by x+6?
The Remainder of x^2-4x+2 divided by x+6 is 62.
2. How to Find Remainder of x^2-4x+2 by x+6 using Remainder Theorem?
Consider x+6 = 0 so that x = -6.
Substitute x = -6 in expression x^2-4x+2 to get the remiander
Thus, x^2-4x+2 divided by x+6 remainder is 62.
3. Where can I obtain detailed solution steps for Remainder Theorem of x^2-4x+2?
The detailed steps for the Remainder Theorem of x^2-4x+2 are compiled exclusively on our output page.