Find Remainder of x^2-2x+2 by x+8 using Remainder Theorem
The Remainder Theorem is an approach to Euclidean polynomial division. According to this theorem, dividing a polynomial P(x) by a factor (x - a), which is not an element of the polynomial, yields a smaller polynomial and a remainder. Here you can check the answer for Find Remainder of x^2-2x+2 by x+8 using Remainder Theorem.
Ex: x^2+2x+1,x+1 (or) x^2-1,x-1 (or) x^3-1,x+1
How to Find Remainder of x^2-2x+2 by x+8 using Remainder Theorem?
Let p(x) = x^2-2x+2
The zero of x+8 is = -8.
So after P(x) is divided by x+8 we get the remainder i.e. P(-8).
Now, p(-8) = x^2-2x+2 .
= (2)+(x^2)+(-2.x)
By putting x = (-8) we can rewrite it as
= (2)+((-8)^2)+(-2.(-8))
= (2)+(64)+(16)
= 82
∴The remainder of given polynomial is 82.
FAQs on Remainder Theorem of x^2-2x+2 by x+8
1. What is the remainder of x^2-2x+2 by x+8?
The Remainder of x^2-2x+2 divided by x+8 is 82.
2. How to Find Remainder of x^2-2x+2 by x+8 using Remainder Theorem?
Consider x+8 = 0 so that x = -8.
Substitute x = -8 in expression x^2-2x+2 to get the remiander
Thus, x^2-2x+2 divided by x+8 remainder is 82.
3. Where can I obtain detailed solution steps for Remainder Theorem of x^2-2x+2?
The detailed steps for the Remainder Theorem of x^2-2x+2 are compiled exclusively on our output page.