Find Remainder of 5x^3+x^2+x-8 by x+1 using Remainder Theorem
The Remainder Theorem is an approach to Euclidean polynomial division. According to this theorem, dividing a polynomial P(x) by a factor (x - a), which is not an element of the polynomial, yields a smaller polynomial and a remainder. Here you can check the answer for Find Remainder of 5x^3+x^2+x-8 by x+1 using Remainder Theorem.
Ex: x^2+2x+1,x+1 (or) x^2-1,x-1 (or) x^3-1,x+1
How to Find Remainder of 5x^3+x^2+x-8 by x+1 using Remainder Theorem?
Let p(x) = 5x^3+x^2+x-8
The zero of x+1 is = -1.
So after P(x) is divided by x+1 we get the remainder i.e. P(-1).
Now, p(-1) = 5x^3+x^2+x-8 .
= (-8)+(x)+(x^2)+(5.x^3)
By putting x = (-1) we can rewrite it as
= (-8)+((-1))+((-1)^2)+(5.(-1)^3)
= (-8)+(-1)+(1)+(-5)
= -13
∴The remainder of given polynomial is -13.
FAQs on Remainder Theorem of 5x^3+x^2+x-8 by x+1
1. What is the remainder of 5x^3+x^2+x-8 by x+1?
The Remainder of 5x^3+x^2+x-8 divided by x+1 is -13.
2. How to Find Remainder of 5x^3+x^2+x-8 by x+1 using Remainder Theorem?
Consider x+1 = 0 so that x = -1.
Substitute x = -1 in expression 5x^3+x^2+x-8 to get the remiander
Thus, 5x^3+x^2+x-8 divided by x+1 remainder is -13.
3. Where can I obtain detailed solution steps for Remainder Theorem of 5x^3+x^2+x-8?
The detailed steps for the Remainder Theorem of 5x^3+x^2+x-8 are compiled exclusively on our output page.