Factoring Binomials as Sum or difference of cubes Calculator tool is helpful to find the factors of a^3+27 with the sum or difference of cubes process. Get the manual process for Finding Factoring of a^3+27 Using Sum or Difference of Cubes here.

Use '^' for exponent

The given expression is x^3-8y^3

By separating each expression we get

(x^3-8y^3)

If we multiply the below expression:

(a-b)(a^2+ab+b^2)

=a (a^2 + a b + b^2) - b (a^2 + a b + b^2)

=a a^2+a^2 (- b)+a a b+a (- b) b+a b^2- b b^2

=a^3 - b^3

So we got the formula of **a ^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})**

The given Polynomial is x^3-8y^3

By applying **a ^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})**

=(x^1-8y^1)(x^2+x^18y^1+8y^2)

After getting indivisual factoring we can cancelout similar terms and The final result will be (x - 2 y) (x^2 + 2 x y + 4 y^2)

**1. What are the factors for a x^3-8y^3 using the sum or difference of cubes?**

The factor for x^3-8y^3 is (x - 2 y) (x^2 + 2 x y + 4 y^2)

**2. How can I use the sum or difference of cubes method to factorize the given equation?**

You can first find the factors of the given equation x^3-8y^3, then by performing simple mathematical calculations you can get the desired factors.