Factoring Binomials as Sum or difference of cubes Calculator tool is helpful to find the factors of a^3+27 with the sum or difference of cubes process. Get the manual process for Finding Factoring of a^3+27 Using Sum or Difference of Cubes here.
Use '^' for exponent
The given expression is x^3-8y^3
By separating each expression we get
If we multiply the below expression:
=a (a^2 + a b + b^2) - b (a^2 + a b + b^2)
=a a^2+a^2 (- b)+a a b+a (- b) b+a b^2- b b^2
=a^3 - b^3
So we got the formula of a3-b3=(a-b)(a2+ab+b2)
The given Polynomial is x^3-8y^3
By applying a3-b3=(a-b)(a2+ab+b2)
After getting indivisual factoring we can cancelout similar terms and The final result will be (x - 2 y) (x^2 + 2 x y + 4 y^2)
1. What are the factors for a x^3-8y^3 using the sum or difference of cubes?
The factor for x^3-8y^3 is (x - 2 y) (x^2 + 2 x y + 4 y^2)
2. How can I use the sum or difference of cubes method to factorize the given equation?
You can first find the factors of the given equation x^3-8y^3, then by performing simple mathematical calculations you can get the desired factors.