Factoring Binomials as Sum or difference of cubes Calculator tool is helpful to find the factors of a^3+27 with the sum or difference of cubes process. Get the manual process for Finding Factoring of a^3+27 Using Sum or Difference of Cubes here.

Use '^' for exponent

The given expression is x^3-1

By separating each expression we get

(x^3-1)

The given polynomial is (x^3-1)

The polynomial can be written as x^3 - 1

=(x)(x^2)+(-1)(x^2)+(x)(x)+(-1)(x)+(x)(1)+(-1)(1)

=(x)((x2 + x + 1))+(-1)((x2 + x + 1))

=(x - 1) (x^2 + x + 1)

After getting indivisual factoring we can cancelout similar terms and The final result will be (x - 1) (x^2 + x + 1)

**1. What are the factors for a x^3-1 using the sum or difference of cubes?**

The factor for x^3-1 is (x - 1) (x^2 + x + 1)

**2. How can I use the sum or difference of cubes method to factorize the given equation?**

You can first find the factors of the given equation x^3-1, then by performing simple mathematical calculations you can get the desired factors.