Factoring Binomials as Sum or difference of cubes Calculator tool is helpful to find the factors of a^3+27 with the sum or difference of cubes process. Get the manual process for Finding Factoring of a^3+27 Using Sum or Difference of Cubes here.

Use '^' for exponent

The given expression is 2^3-x^3

By separating each expression we get

(2^3-x^3)

If we multiply the below expression:

(a-b)(a^2+ab+b^2)

=a (a^2 + a b + b^2) - b (a^2 + a b + b^2)

=a a^2+a^2 (- b)+a a b+a (- b) b+a b^2- b b^2

=a^3 - b^3

So we got the formula of **a ^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})**

The given Polynomial is 2^3-x^3

By applying **a ^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})**

=(2^1-x^1)(2^2+2^1x^1+x^2)

After getting indivisual factoring we can cancelout similar terms and The final result will be - (x - 2) (x^2 + 2 x + 4)

**1. What are the factors for a 2^3-x^3 using the sum or difference of cubes?**

The factor for 2^3-x^3 is - (x - 2) (x^2 + 2 x + 4)

**2. How can I use the sum or difference of cubes method to factorize the given equation?**

You can first find the factors of the given equation 2^3-x^3, then by performing simple mathematical calculations you can get the desired factors.