Factoring Binomials as Sum or difference of cubes Calculator tool is helpful to find the factors of a^3+27 with the sum or difference of cubes process. Get the manual process for Finding Factoring of a^3+27 Using Sum or Difference of Cubes here.
Use '^' for exponent
The given expression is a^6+b^6
By separating each expression we get
If we multiply the below expression:
=a (a^2 - a b + b^2) + b (a^2 - a b + b^2)
=a a^2+a^2 b- a a b- a b b+a b^2+b b^2
=a^3 + b^3
So we got the formula of a3+b3=(a+b)(a2-ab+b2)
By applying a3+b3=(a+b)(a2-ab+b2)
After getting indivisual factoring we can cancelout similar terms and The final result will be (a^2 + b^2) (a^4 - a^2 b^2 + b^4)
1. What are the factors for a a^6+b^6 using the sum or difference of cubes?
The factor for a^6+b^6 is (a^2 + b^2) (a^4 - a^2 b^2 + b^4)
2. How can I use the sum or difference of cubes method to factorize the given equation?
You can first find the factors of the given equation a^6+b^6, then by performing simple mathematical calculations you can get the desired factors.